Doubt: What actually happens in a cnot gate when the control cubit is in a superposition?
Summarize this article with:
On quantum entanglement, the bell state is created when a superposition qubit influence another qubit. After it reaches the entangled state it the qubits state cannot be inferred individually, as it stays in 2^-0.5 * (|00> + |11>) and it cant be factorized. My doubt is when the 1st qubit is in superposition and the 2nd qubit is modified using cnot gate, the 2nd qubit should and will be in either |0> or |1> state with probability of the 1st qubit. So we say its in superposition but it should actually in either |0> or |1>, to preserve the no-cloning rule. So wouldn't it be possible that after the entanglement we measure the 2nd qubit and use a parameterized gate with parameters to bring back the 1st qubit to a hermitian matrix eigen value state, and measure the 1qubit. So if the 1st qubit was originally in state |0> and after bringing it back using a parameterized gate the measured value should be |0> while the 2nd qubit should so variations. Can someone explain what's actually happening. submitted by /u/__AzureDragon__ [link] [comments]