Doubt regarding the relative phase of the qubit

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I am working on my thesis on quantum computing and have some questions about the relative phase of a qubit based on the Bloch sphere representation. As I understand it—and I like to explain it with this analogy—the probability amplitudes of obtaining a single state, 0 or 1, would be circles like the sides of a coin, and from what I’ve read, the larger this circle is, the greater the probability. On the other hand, there is the fixed phase, which cannot be measured and has no effect, and the relative phase, which is measured by the rotation about the vertical axis on that circle; I think I understand that part well. Looking at it mathematically, I understand that with the same probability amplitude, different results can be obtained depending on the phase, but I can’t quite grasp how this rotation affects the results. Could someone explain this to me better? submitted by /u/Timely_Injury8046 [link] [comments]
