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Question: what happens when you apply a Hadamard gate to a qubits that's in arbitrary superposition?
Reddit r/QuantumComputing (RSS)
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⚡ Quantum Brief
A Reddit user posed a question about applying a Hadamard gate to a qubit in an arbitrary superposition, extending beyond the known cases of |0⟩ and |1⟩ states.
The query focuses on how the Hadamard gate transforms a qubit in the general state α|0⟩ + β|1⟩, where α and β are complex probability amplitudes.
The Hadamard gate’s standard behavior—mapping |0⟩ to |+⟩ and |1⟩ to |−⟩—serves as the baseline for understanding its effect on superpositions.
Mathematically, the result is a new superposition where the amplitudes are redistributed via the Hadamard matrix, yielding (α + β)|0⟩ + (α − β)|1⟩/√2.
This highlights the gate’s role in creating interference patterns, a key mechanism for quantum algorithms like Grover’s or Shor’s.

Summarize this article with:
I know that applying Hadamard gate to |0> causes it to become |+> and applying it to |1> causes it to become |->. My question is what happens when the qubits is in a arbitrary superposition like α|0> + β|1>. submitted by /u/Lower-Bug5563 [link] [comments]
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quantum-hardware
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Source: Reddit r/QuantumComputing (RSS)
